The cathode of a photoelectric cell is change | vedclass

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(A) The photoelectric current in a cell depends on the number of photoelectrons emitted per unit time.This number is directly proportional to the numb

Vedclass · Accepted Answer

$I_1 = I_2$

Vedclass · Answer

(A) The photoelectric current in a cell depends on the number of photoelectrons emitted per unit time.This number is directly proportional to the number of incident photons per unit time (intensity of light),provided the energy of each incident photon $(hv)$ is greater than the work function $(W)$ of the metal surface.Since the intensity of the incident light remains unchanged and the condition $hv > W_2$ (which implies $hv > W_1$ as well) is satisfied,the rate of emission of photoelectrons remains the same.Therefore,the photoelectric current remains unchanged,i.e.,$I_1 = I_2$.

The cathode of a photoelectric cell is changed such that the work function changes from $W_1$ to $W_2$ $(W_2 > W_1)$. If the current before and after change are $I_1$ and $I_2$,all other conditions remaining unchanged,then (assuming $hv > W_2$):

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